If $\log _{(3 x-1)}(x-2)=\log _{\left(9 x^2-6 x+1\right)}\left(2 x^2-10 x-2\right)$, then $x$ equals
If $\log _{(3 x-1)}(x-2)=\log _{\left(9 x^2-6 x+1\right)}\left(2 x^2-10 x-2\right)$, then $x$ equals
- [KVPY 2015]
- A
$9-\sqrt{15}$
- B
$3+\sqrt{15}$
- C
$2+\sqrt{5}$
- D
$6-\sqrt{5}$
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