Let r₁, r₂, r₃ be roots of equation x^3 -2x^2 + 4x + 5074 = 0 , then value of (r?

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4-2.Quadratic Equations and Inequations

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Let $r_1, r_2, r_3$ be roots of equation $x^3 -2x^2 + 4x + 5074 = 0$, then the value of $(r_1 + 2)(r_2 + 2)(r_3 + 2)$ is

A

$5050$

B

$-5050$

C

$-5066$

D

$-5068$

Solution

$x^3 -2x^2 + 4x + 5074 = (x -r_1) (x -r_2) (x -r_3)$

put $r = -2$

$-5050 = (r_1 + 2) (r_2 + 2) (r_3 + 2)$.

Standard 11

Mathematics

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