If $\frac{{ }^{11} C_1}{2}+\frac{{ }^{11} C_2}{3}+\ldots . .+\frac{{ }^{11} C_9}{10}=\frac{n}{m}$ with $\operatorname{gcd}(n, m)=1$, then $n+m$ is equal to

  • [JEE MAIN 2024]
  • A

    $2041$

  • B

    $2024$

  • C

    $2014$

  • D

    $2043$

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