If ${\log _{12}}27 = a,$ then ${\log _6}16 = $
If ${\log _{12}}27 = a,$ then ${\log _6}16 = $
- A
$2.{{3 - a} \over {3 + a}}$
- B
$3.{{3 - a} \over {3 + a}}$
- C
$4.{{3 - a} \over {3 + a}}$
- D
None of these
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