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Basic of Logarithms
medium
If $x = {\log _3}5,\,\,\,y = {\log _{17}}25,$ which one of the following is correct
A
$x < y$
B
$x = y$
C
$x > y$
D
None of these
Solution
(c) $y = {\log _{17}}25 = 2{\log _{17}}5$;
$\therefore {1 \over y} = {1 \over 2}{\log _5}17$
${1 \over x} = {\log _5}3 = {1 \over 2}{\log _5}9$.
Clearly, ${1 \over y} > {1 \over x}$; $\therefore x > y$
Standard 11
Mathematics