If a,;b,;c,;d,;e,;f are in A.P., then the val | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) $a,\;b,\;c,\;d,\;e,\;f$ are in $A.P.$

So $b - a = c - b = d - c = e - d = f - e = K$

Where $K$ is a common difference.

Now, $d - c = e -

Vedclass · Accepted Answer

$2(d - c)$

Vedclass · Answer

(c) $a,\;b,\;c,\;d,\;e,\;f$ are in $A.P.$

So $b - a = c - b = d - c = e - d = f - e = K$

Where $K$ is a common difference.

Now, $d - c = e - d$

$ \Rightarrow $$e + c = 2d$.

$e{\rm{-}}c + {\rm{2}}c = 2d $

$\Rightarrow e - c = 2(d - c)$.

Trick : Check by putting $a = 1,\;b = 2,\;c = 3,\;d = 4,\;e = 5$ and $f = 6$.

If $a,\;b,\;c,\;d,\;e,\;f$ are in $A.P.$, then the value of $e - c$ will be

Similar Questions

If $n$ be odd or even, then the sum of $n$ terms of the series $1 - 2 + $ $3 - $$4 + 5 - 6 + ......$ will be

If $\log _{3} 2, \log _{3}\left(2^{x}-5\right), \log _{3}\left(2^{x}-\frac{7}{2}\right)$ are in an arithmetic progression, then the value of $x$ is equal to $.....$

The $20^{\text {th }}$ term from the end of the progression $20,19 \frac{1}{4}, 18 \frac{1}{2}, 17 \frac{3}{4}, \ldots .,-129 \frac{1}{4}$ is :-

If ${a^{1/x}} = {b^{1/y}} = {c^{1/z}}$ and $a,\;b,\;c$ are in $G.P.$, then $x,\;y,\;z$ will be in

If $\frac{a}{b},\frac{b}{c},\frac{c}{a}$ are in $H.P.$, then