Gujarati
4-2.Quadratic Equations and Inequations
medium

यदि $x$ वास्तविक है तथा $x + 2 > \sqrt {x + 4} $ को सन्तुष्ट करता है, तब

A

$x < - 2$

B

$x > 0$

C

$ - 3 < x < 0$

D

$ - 3 < x < 4$

Solution

(b) दिया है, $x + 2 > \,\sqrt {x + 4} $$ \Rightarrow {(x + 2)^2}\,\, > (x + 4)$

$ \Rightarrow {x^2} + 4x + 4 > x + 4$$ \Rightarrow {x^2} + 3x > 0$

$ \Rightarrow x(x + 3) > 0$

$⇒ x < -3$ या $x > 0$ $ \Rightarrow \,x > 0$.

Standard 11
Mathematics

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