If (x + 1) is a factor of {x^4} - (p - 3){x^3 | vedclass

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Question

(a) If $(x + 1)$ is a factor of

${x^4} - (p - 3){x^3} - (3p - 5){x^2} + (2p - 7)x + 6$ , then by putting $x = - 1$, we get

$1 + (p - 3) - (3p -

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(a) If $(x + 1)$ is a factor of

${x^4} - (p - 3){x^3} - (3p - 5){x^2} + (2p - 7)x + 6$ , then by putting $x = - 1$, we get

$1 + (p - 3) - (3p - 5) - (2p - 7) + 6 = 0$

==> $ - 4p = - 16\,\,\, \Rightarrow p = 4$.

If $(x + 1)$ is a factor of ${x^4} - (p - 3){x^3} - (3p - 5){x^2}$ $ + (2p - 7)x + 6$, then $p = $

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