If $a < 0$ then the inequality $a{x^2} - 2x + 4 > 0$ has the solution represented by

  • A

    $\frac{{1 + \sqrt {1 - 4a} }}{a} > x > \frac{{1 - \sqrt {1 - 4a} }}{a}$

  • B

    $x < \frac{{1 - \sqrt {1 - 4a} }}{a}$

  • C

    $x < 2$

  • D

    $2 > x > \frac{{1 + \sqrt {1 - 4a} }}{a}$

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