If $a < 0$ then the inequality $a{x^2} - 2x + 4 > 0$ has the solution represented by
If $a < 0$ then the inequality $a{x^2} - 2x + 4 > 0$ has the solution represented by
- A
$\frac{{1 + \sqrt {1 - 4a} }}{a} > x > \frac{{1 - \sqrt {1 - 4a} }}{a}$
- B
$x < \frac{{1 - \sqrt {1 - 4a} }}{a}$
- C
$x < 2$
- D
$2 > x > \frac{{1 + \sqrt {1 - 4a} }}{a}$
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