7.Binomial Theorem
hard

જો ${(1 + x + {x^2})^n}$ ના વિસ્તરણમાં ${a_r}$ એ ${x^r}$ નો સહગુણક દર્શાવે છે ,તો ${a_1} - 2{a_2} + 3{a_3} - .... - 2n\,{a_{2n}} = $

A

$0$

B

$n$

C

$-n$

D

$2n$

Solution

(c) Let us take ${a_0} + {a_1}x + {a_2}{x^2} + ….. + {a_{2n}}{x^{2n}} = {(1 + x + {x^2})^n}$

Differentiating with respect to x on both sides ${a_1} + 2{a_2}x + … + 2n\,{a_{2n}}{x^{2n – 1}}$ = $n{(1 + x + {x^2})^{n – 1}}(2x + 1)$

Put $x = -1$  ==> ${a_1} – 2{a_2} + 3{a_3} – …. + 2n\,{a_{2n}} = – n$.

Standard 11
Mathematics

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