- Home
- Standard 12
- Mathematics
3 and 4 .Determinants and Matrices
easy
જો $\left| {\,\begin{array}{*{20}{c}}{x + 1}&1&1\\2&{x + 2}&2\\3&3&{x + 3}\end{array}\,} \right| = 0,$ તો $x =$
A
$0, -6$
B
$0, 6$
C
$6$
D
$-6$
Solution
(a) From options put $x = 0,\,6$ and $-6$. Then only option $ (a) $ is satisfying.
Standard 12
Mathematics