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3 and 4 .Determinants and Matrices
easy
यदि $A = \left[ {\begin{array}{*{20}{c}}1&0&0\\0&1&0\\a&b&{ - 1}\end{array}} \right]$, तब ${A^2} = $
A
इकाई आव्यूह
B
शून्य आव्यूह
C
$A$
D
$-A$
Solution
(a) ${A^2} = A.\,A = \left[ {\begin{array}{*{20}{c}}1&0&0\\0&1&0\\a&b&{ – 1}\end{array}} \right]\,\left[ {\begin{array}{*{20}{c}}1&0&0\\0&1&0\\a&b&{ – 1}\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}1&0&0\\0&1&0\\0&0&1\end{array}} \right] = I$
Standard 12
Mathematics