If $\tan A = \frac{1}{2},\tan B = \frac{1}{3},$ then $\cos 2A = $
If $\tan A = \frac{1}{2},\tan B = \frac{1}{3},$ then $\cos 2A = $
- A
$\sin B$
- B
$\sin 2B$
- C
$\sin 3B$
- D
None of these
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