If A + B + C = {180^o}, then the value of cot | vedclass

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Question

(c) $A + B + C = {180^o}$, 

$	herefore \,\frac{A}{2} + \frac{B}{2} = {90^o} - \frac{C}{2}$

$	herefore \cot \left( {\frac{A}{2} + \frac{B}

Vedclass · Accepted Answer

$\cot \frac{A}{2}\cot \frac{B}{2}\cot \frac{C}{2}$

Vedclass · Answer

(c) $A + B + C = {180^o}$, 

$	herefore \,\frac{A}{2} + \frac{B}{2} = {90^o} - \frac{C}{2}$

$	herefore \cot \left( {\frac{A}{2} + \frac{B}{2}} ight) = \cot \left( {{{90}^o} - \frac{C}{2}} ight)$

or $\frac{{\cot \frac{A}{2}\,.\,\cot \frac{B}{2}\, - 1}}{{\cot \frac{B}{2}\, + \,\cot \frac{A}{2}}} = 	an \frac{C}{2} = \frac{1}{{\cot \frac{C}{2}}}$ 

or $\left( {\cot \frac{A}{2}\cot \frac{B}{2} - 1} ight)\cot \frac{C}{2} = \cot \frac{B}{2} + \cot \frac{A}{2}$ 

$\cot \frac{A}{2}\,.\,\cot \frac{B}{2}\,.\,\cot \frac{C}{2} = \cot \frac{C}{2} + \cot \frac{B}{2}$ $ + \cot \frac{A}{2}.$

If $A + B + C = {180^o},$ then the value of $\cot \frac{A}{2} + \cot \frac{B}{2} + \cot \frac{C}{2}$ will be

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