If frac{{2sin alpha }}{{{ 1 + cos alpha + sin | vedclass

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Question

(b) We have, $\frac{{2\sin \alpha }}{{1 + \cos \alpha + \sin \alpha }} = y$

then, $\frac{{4\sin \frac{\alpha }{2}\cos \frac{\alpha }{2}}}{{2{{\cos

Vedclass · Accepted Answer

$y$

Vedclass · Answer

(b) We have, $\frac{{2\sin \alpha }}{{1 + \cos \alpha + \sin \alpha }} = y$

then, $\frac{{4\sin \frac{\alpha }{2}\cos \frac{\alpha }{2}}}{{2{{\cos }^2}\frac{\alpha }{2} + 2\sin \frac{\alpha }{2}\cos \frac{\alpha }{2}}} = y$

==> $\frac{{2\sin \frac{\alpha }{2}}}{{\cos \frac{\alpha }{2} + \sin \frac{\alpha }{2}}} 	imes \frac{{\left( {\sin \frac{\alpha }{2} + \cos \frac{\alpha }{2}} ight)}}{{\left( {\sin \frac{\alpha }{2} + \cos \frac{\alpha }{2}} ight)}} = y$

==> $\frac{{1 - \cos \alpha + \sin \alpha }}{{1 + \sin \alpha }} = y$.

If $\frac{{2\sin \alpha }}{{\{ 1 + \cos \alpha + \sin \alpha \} }} = y,$ then $\frac{{\{ 1 - \cos \alpha + \sin \alpha \} }}{{1 + \sin \alpha }} = $

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