If sin t + cos t = frac{1}{5} then tan frac{t}{2} is equal to :

English

Gujarati

Hindi

3.Trigonometrical Ratios, Functions and Identities

normal

If $sin t + cos t = \frac{1}{5}$ then $tan \frac{t}{2}$ is equal to :

A

$-1$

B

$-\frac{1}{3}$

C

$2$

D

Both $(b)$ and $(c)$

Solution

$sin t$ and $cos t$ in tangent of half the angle

$\Rightarrow (3y + 1)(y – 2) = 0$

$ \Rightarrow y = 2$ or $-1/3$ where $y = tan(t/2)$

Standard 11

Mathematics

Share

Similar Questions

If a $cos^3 \alpha + 3a \,cos\, \alpha \, sin^2\, \alpha = m$ and $asin^3\, \alpha + 3a \, cos^2\, \alpha \,sin\, \alpha = n$ . Then $(m + n)^{2/3} + (m – n)^{2/3}$ is equal to :

hard

If $\alpha + \beta = \frac{\pi }{2}$ and $\beta + \gamma = \alpha ,$ then $\tan \,\alpha $ equals

medium

(IIT-2001)

Value of $\frac{{4\sin {9^o}\sin {{21}^o}\sin {{39}^o}\sin {{51}^o}\sin {{69}^o}\sin {{81}^o}}}{{\sin {{54}^o}}}$ is equal to

normal

Prove that $\tan 4 x=\frac{4 \tan x\left(1-\tan ^{2} x\right)}{1-6 \tan ^{2} x+\tan ^{4} x}$

medium

$\sqrt {2 + \sqrt {2 + 2\cos 4\theta } } = $

easy