यदि $cos A = {3\over 4} , $ तब $32\sin \left( {\frac{A}{2}} \right)\sin \left( {\frac{{5A}}{2}} \right) = $

यदि $A + B + C = \frac{{3\pi }}{2},$ तब  $\cos 2A + \cos 2B + \cos 2C = $

$\frac{{\tan A + \sec A - 1}}{{\tan A - \sec A + 1}} = $

$\frac{1}{{\sin 10^\circ }} - \frac{{\sqrt 3 }}{{\cos 10^\circ }} =$

$\sqrt {2 + \sqrt {2 + 2\cos 4\theta } } = $

$\cos A + \cos (240^\circ + A) + \cos (240^\circ - A) = $