If A + B + C = {180^o}, then frac{{tan A + tan B + tan C}}{{tan A,.,tan B,.,tan C}} =

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3.Trigonometrical Ratios, Functions and Identities

easy

If $A + B + C = {180^o},$ then $\frac{{\tan A + \tan B + \tan C}}{{\tan A\,.\,\tan B\,.\,\tan C}} = $

A

$0$

B

$2$

C

$1$

D

$-1$

Solution

(c) Since ${S_1} = {S_3} \Rightarrow \frac{{{S_1}}}{{{S_3}}} = 1$.

Standard 11

Mathematics

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