यदि a,cos 2theta + b,sin 2theta = c के | vedclass

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Question

(b) $a\cos 2	heta + b\sin 2	heta = c$

==> $a\left( {\frac{{1 - {{	an }^2}	heta }}{{1 + {{	an }^2}	heta }}} ight) + b\frac{{2	an 	heta

Vedclass · Accepted Answer

$\frac{{2b}}{{c + a}}$

Vedclass · Answer

(b) $a\cos 2	heta + b\sin 2	heta = c$

==> $a\left( {\frac{{1 - {{	an }^2}	heta }}{{1 + {{	an }^2}	heta }}} ight) + b\frac{{2	an 	heta }}{{1 + {{	an }^2}	heta }} = c$

$ \Rightarrow $ $a - a{	an ^2}	heta + 2b	an 	heta = c + c{	an ^2}	heta $

$ \Rightarrow $$ - (a + c){	an ^2}	heta + 2b\,	an 	heta + (a - c) = 0$

$	herefore 	an \alpha + 	an \beta = - \frac{{2b}}{{ - (c + a)}} = \frac{{2b}}{{c + a}}$ .

यदि $a\,\cos 2\theta + b\,\sin 2\theta = c$ के दो हल $\alpha$ और $\beta$ हों, तो $\tan \alpha + \tan \beta $ का मान होगा

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