If $A$ lies in the third quadrant and $3\,\tan A - 4 = 0,$ then $5\,\sin 2A + 3\,\sin A + 4\,\cos A = $
If $A$ lies in the third quadrant and $3\,\tan A - 4 = 0,$ then $5\,\sin 2A + 3\,\sin A + 4\,\cos A = $
- A
$0$
- B
$\frac{{ - 24}}{5}$
- C
$\frac{{24}}{5}$
- D
$\frac{{48}}{5}$
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