- Home
- Standard 11
- Mathematics
Trigonometrical Equations
easy
यदि ${\sin ^2}\theta = \frac{1}{4},$ तो $\theta $ का सर्वव्यापक मान है
A
$2n\pi \pm {( - 1)^n}\frac{\pi }{6}$
B
$\frac{{n\pi }}{2} \pm {( - 1)^n}\frac{\pi }{6}$
C
$n\pi \pm \frac{\pi }{6}$
D
$2n\pi \pm \frac{\pi }{6}$
Solution
(c) ${\sin ^2}\theta = \frac{1}{4} = $${\sin ^2}\frac{\pi }{6}$
$\Rightarrow \theta = n\pi \pm \frac{\pi }{6}$.
Standard 11
Mathematics
