If {sin ^2}θ = frac{1}{4}, then most general value of θ is

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Trigonometrical Equations

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If ${\sin ^2}\theta = \frac{1}{4},$ then the most general value of $\theta $ is

A

$2n\pi \pm {( - 1)^n}\frac{\pi }{6}$

B

$\frac{{n\pi }}{2} \pm {( - 1)^n}\frac{\pi }{6}$

C

$n\pi \pm \frac{\pi }{6}$

D

$2n\pi \pm \frac{\pi }{6}$

Solution

(c) ${\sin ^2}\theta = \frac{1}{4} = $${\sin ^2}\frac{\pi }{6}$

$\Rightarrow \theta = n\pi \pm \frac{\pi }{6}$.

Standard 11

Mathematics

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