If sqrt 2 sec theta + tan theta = 1, then the | vedclass

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Question

(c) $\sqrt 2 \sec 	heta + 	an 	heta = 1 $

$\Rightarrow \frac{{\sqrt 2 }}{{\cos 	heta }} + \frac{{\sin 	heta }}{{\cos 	heta }} = 1$

$ \Righ

Vedclass · Accepted Answer

$2n\pi - \frac{\pi }{4}$

Vedclass · Answer

(c) $\sqrt 2 \sec 	heta + 	an 	heta = 1 $

$\Rightarrow \frac{{\sqrt 2 }}{{\cos 	heta }} + \frac{{\sin 	heta }}{{\cos 	heta }} = 1$

$ \Rightarrow $ $\sin 	heta - \cos 	heta = - \sqrt 2 $

Dividing by $\sqrt 2 $ on both sides, we get 

$\frac{1}{{\sqrt 2 }}\sin 	heta - \frac{1}{{\sqrt 2 }}\cos 	heta = - 1$

$ \Rightarrow $ $\frac{1}{{\sqrt 2 }}\cos 	heta - \frac{1}{{\sqrt 2 }}\sin 	heta = 1 $

$\Rightarrow \cos \,\left( {	heta + \frac{\pi }{4}} ight) = \cos (0)$

$ \Rightarrow $ $	heta + \frac{\pi }{4} = 2n\pi \pm 0$

$\Rightarrow 	heta = 2n\pi - \frac{\pi }{4}$.

If $\sqrt 2 \sec \theta + \tan \theta = 1,$ then the general value $\theta $ is

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