If (2cos x - 1)(3 + 2cos x) = 0,,0 le x le 2p | vedclass

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Question

(b) $(2\cos x - 1)\,\,(3 + 2\cos x) = 0$

Then $\cos x = \frac{1}{2}{m{ as}}\,{m{ }}\cos x 
e \frac{{ - 3}}{2}$

$ \Rightarrow $ $x = 2n\pi \

Vedclass · Accepted Answer

$\frac{\pi }{3},\frac{{5\pi }}{3}$

Vedclass · Answer

(b) $(2\cos x - 1)\,\,(3 + 2\cos x) = 0$

Then $\cos x = \frac{1}{2}{m{ as}}\,{m{ }}\cos x 
e \frac{{ - 3}}{2}$

$ \Rightarrow $ $x = 2n\pi \pm \frac{\pi }{3};\,\,\left\{ \begin{array}{l}{m{ \,for \,\,}}n = 0,\,\,x = \frac{\pi }{3},\,\frac{{5\pi }}{3}\{m{ \,for\,\, }}n = 1,\,\,x = \frac{{5\pi }}{3}\end{array} ight\}$

If $(2\cos x - 1)(3 + 2\cos x) = 0,\,0 \le x \le 2\pi $, then $x = $

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