જો tan (pi cos theta ) = cot (pi sin theta ), | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) $	an (\pi \cos 	heta ) = 	an \left( {\frac{\pi }{2} - \pi \sin 	heta } ight)$

$	herefore $ $\,\sin 	heta + \cos 	heta = \frac{1}{2}$

Vedclass · Accepted Answer

$\frac{1}{{2\sqrt 2 }}$

Vedclass · Answer

(a) $	an (\pi \cos 	heta ) = 	an \left( {\frac{\pi }{2} - \pi \sin 	heta } ight)$

$	herefore $ $\,\sin 	heta + \cos 	heta = \frac{1}{2}$

$ \Rightarrow \,\cos \left( {	heta - \frac{\pi }{4}} ight) = \frac{1}{{2\sqrt 2 }}$.

જો $\tan (\pi \cos \theta ) = \cot (\pi \sin \theta ),$ તો $\cos \left( {\theta - \frac{\pi }{4}} \right) =$

Similar Questions

જો $\cos 2\theta + 3\cos \theta = 0$, તો $\theta $ નો વ્યાપક ઉકેલ મેળવો.

જો $2\,cos\,\theta + sin\, \theta \, = 1$ $\left( {\theta \ne \frac{\pi }{2}} \right)$ , તો $7\, cos\,\theta + 6\, sin\, \theta $ = .....

સમીકરણ $2{\sin ^2}\theta - 3\sin \theta - 2 = 0$ નું સમાધાન કરે તેવા $\theta $ નો વ્યાપક ઉકેલ મેળવો.

સમીકરણ ${2^{\tan \,\,\left( {x\,\, - \,\,{\textstyle{\pi \over 4}}} \right)}}$ $- 2$${\left( {0.25} \right)^{\frac{{{{\sin }^2}\,\left( {x\,\, - \,\,{\textstyle{\pi \over 4}}} \right)}}{{\cos \,\,2x}}}}$ $+ 1 = 0$ નો ઉકેલગણ.......... છે

$\sum\limits_{r = 1}^{100} {\frac{{\tan \,{2^{r - 1}}}}{{\cos \,{2^r}}}} $ =