यदि /cot (alpha + beta ) = 0, तब | vedclass

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Question

दिया गया है, $\cot (\alpha  + \beta ) = 0 \Rightarrow \cos (\alpha  + \beta ) = 0$

$\Rightarrow$ $\alpha  + \beta  = (2n +

Vedclass · Accepted Answer

$\sin \alpha $

Vedclass · Answer

दिया गया है, $\cot (\alpha  + \beta ) = 0 \Rightarrow \cos (\alpha  + \beta ) = 0$

$\Rightarrow$ $\alpha  + \beta  = (2n + 1)\frac{\pi }{2},n \in I$

$	herefore$ $\sin (\alpha  + 2\beta ) = \sin (2\alpha  + 2\beta  - \alpha )$

$=\sin {m{ }}[(2n + 1){m{ }}\pi  - \alpha ]$

$ = \sin (\,2n\pi  + \pi  - \alpha \,)$ = $\sin (\,\pi  - \alpha \,)\, = \sin \alpha $.

यदि $/cot (\alpha + \beta ) = 0,$ तब $\sin (\alpha + 2\beta ) = $

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