Trigonometrical Equations
medium

यदि $12{\cot ^2}\theta  - 31\,{\rm{cosec }}\theta  + {\rm{32}} = {\rm{0}}$, तो $\sin \theta $ का मान है  

A

$\frac{3}{5}$ या $1$

B

$\frac{{2}}{3}$ या $\frac{{ - 2}}{3}$

C

$\frac{4}{5}$ या $\frac{3}{4}$

D

$ \pm \frac{1}{2}$

Solution

$12{\cot ^2}\theta  – 31\cos ec\theta  + 32 = 0$

$12({\rm{cos}}{\rm{e}}{{\rm{c}}^2}\theta  – 1) – 31{\rm{cos}}{\rm{ec }}\theta  + {\rm{32}} = {\rm{0}}$

$12{\rm{cos}}{\rm{e}}{{\rm{c}}^2}\theta  – 31\,{\rm{cos}}{\rm{ec }}\theta  + {\rm{20}} = {\rm{0}}$

$12\,{\rm{cos}}{\rm{e}}{{\rm{c}}^2}\theta  – 16\,\,{\rm{cos}}{\rm{ec }}\theta  – 15\,{\rm{cos}}{\rm{ec}}\theta  + 20 = {\rm{0}}$

$(4\cos {\rm{ec}}\theta  – 5)(3\cos {\rm{ec}}\theta  – 4) = 0$

${\rm{cos}}{\rm{ec}}\theta  = \frac{5}{4},\frac{4}{3}$; 

$\therefore$  $\sin \theta  = \frac{4}{5},\frac{3}{4}$.

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.