If $f(x) = \frac{x}{{1 + x}}$, then ${f^{ - 1}}(x)$ is equal to
If $f(x) = \frac{x}{{1 + x}}$, then ${f^{ - 1}}(x)$ is equal to
- A
$\frac{{(1 + x)}}{x}$
- B
$\frac{1}{{(1 + x)}}$
- C
$\frac{{(1 + x)}}{{(1 - x)}}$
- D
$\frac{x}{{(1 - x)}}$
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