- Home
- Standard 12
- Mathematics
1.Relation and Function
easy
જો $f$ એ મહતમ પૂર્ણાક વિધેય હોય અને $g$ એ માનાંક વિધેય હોય, તો $(gof)\left( { - \frac{5}{3}} \right) - (fog)\left( { - \frac{5}{3}} \right) = $
A
$1$
B
$-1$
C
$2$
D
$4$
Solution
(a) Given $(gof)\,\,\left( {\frac{{ – 5}}{3}} \right) – (fog)\,\left( {\frac{{ – 5}}{3}} \right)$
$ = g\,\left\{ {f\left( {\frac{{ – 5}}{3}} \right)} \right\} – f\left\{ {g\left( {\frac{{ – 5}}{3}} \right)} \right\} = g( – 2) – f\left( {\frac{5}{3}} \right) = 2 – 1 = 1$ .
Standard 12
Mathematics