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14.Probability
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If $P\,({A_1} \cup {A_2}) = 1 - P(A_1^c)\,P(A_2^c)$ where $c$ stands for complement, then the events ${A_1}$ and ${A_2}$ are
A
Mutually exclusive
B
Independent
C
Equally likely
D
None of these
Solution
(b) $P({A_1} \cup {A_2}) = 1 – [1 – P({A_1})]\,[1 – P({A_2})]$
$ = P({A_1}) + P({A_2}) – P({A_1})\,.\,P({A_2})$.
Standard 11
Mathematics
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