- Home
- Standard 11
- Mathematics
14.Probability
medium
If $P(A \cup B) = 0.8$ and $P(A \cap B) = 0.3,$ then $P(\bar A) + P(\bar B) = $
A
$0.3$
B
$0.5$
C
$0.7$
D
$0.9$
Solution
(d) $P(A'\, \cap B')\, = 1 – P(A \cup B)\, = 1 – 0.8 = 0.2$
$P(A' \cup B') = 1 – P(A \cap B) = 1 – 0.3 = 0.7$
$P(A' \cup B') = P(A')\, + \,P(B') – P(A' \cap B')$
$⇒ \,0.7\, = P(A') + P(B') – 0.2$ $⇒$ $ P(A')+ P(B')=09 $.
Standard 11
Mathematics