Gujarati
14.Probability
medium

यदि $P\,(A) = 0.4,\,\,P\,(B) = x,\,\,P\,(A \cup B) = 0.7$ और घटनाएँ $A$ तथा $B$ स्वतन्त्र हों, तो $x= $

A

$\frac{1}{3}$

B

$\frac{1}{2}$

C

$\frac{2}{3}$

D

इनमें से कोई नहीं

Solution

(b) $0.7 = 0.4 + x – 0.4x \Rightarrow x = \frac{1}{2}.$

Standard 11
Mathematics

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