Gujarati
14.Probability
easy

$A$ तथा $B$ एक यादृच्छिक प्रयोग की दो घटनाएँ हैं और $P\,(A) = 0.25$, $P\,(B) = 0.5$ तथा $P\,(A \cap B) = 0.15,$ तो $P\,(A \cap \bar B) = $

A

$0.1$

B

$0.35$

C

$0.15$

D

$0.6$

Solution

(a) चूँकि $P(A \cap \bar B) + P(A \cap B) = P(A)$

$ \Rightarrow P(A \cap \overline B ) = P(A) – P(A \cap B) = 0.25 – 0.15 = 0.1$

Standard 11
Mathematics

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