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14.Probability
easy
यदि $P\,(A) = \frac{1}{4},\,\,P\,(B) = \frac{5}{8}$ तथा $P\,(A \cup B) = \frac{3}{4},$ तो $P\,(A \cap B) = $
A
$\frac{1}{8}$
B
$0$
C
$\frac{3}{4}$
D
$1$
Solution
(a) $P(A \cap B) = \frac{2}{8} + \frac{5}{8} – \frac{6}{8} = \frac{1}{8}.$
Standard 11
Mathematics