- Home
- Standard 11
- Mathematics
14.Probability
medium
यदि $A$ तथा $B$ दो ऐसी घटनाएँ हों कि $P\,(A \cup B)\, + P\,(A \cap B) = \frac{7}{8}$ तथा $P\,(A) = 2\,P\,(B),$ तो $P\,(A) = $
A
$\frac{7}{{12}}$
B
$\frac{7}{{24}}$
C
$\frac{5}{{12}}$
D
$\frac{{17}}{{24}}$
Solution
(a) चूँकि $P(A \cup B) + P(A \cap B) = P(A) + P(B)$$ = P(A) + \frac{{P(A)}}{2}$
$ \Rightarrow \frac{7}{8} = \frac{{3P(A)}}{2} \Rightarrow P(A) = \frac{7}{{12}}.$
Standard 11
Mathematics