Gujarati
14.Probability
normal

यदि $A$ तथा $B$ दो स्वेच्छ घटनायें हो, तब

A

$P(A \cap B) \ge P(A) + P(B)$

B

$P(A \cup B) \le P(A) + P(B)$

C

$P(A \cap B) = P(A) + P(B)$

D

इनमें से कोई नहीं

Solution

(b) $P(A \cup B) = P(A) + P(B) – P(A \cap B) \le P(A) + P(B)$,  $(\because \,\,P(A \cap \,B) \geqslant \,0)$.
.

Standard 11
Mathematics

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