- Home
- Standard 11
- Mathematics
14.Probability
normal
यदि $A$ तथा $B$ दो स्वेच्छ घटनायें हो, तब
A
$P(A \cap B) \ge P(A) + P(B)$
B
$P(A \cup B) \le P(A) + P(B)$
C
$P(A \cap B) = P(A) + P(B)$
D
इनमें से कोई नहीं
Solution
(b) $P(A \cup B) = P(A) + P(B) – P(A \cap B) \le P(A) + P(B)$, $(\because \,\,P(A \cap \,B) \geqslant \,0)$.
.
Standard 11
Mathematics