If theta and phi are acute satisfying sin t | vedclass

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Question

(b) $\sin 	heta = \frac{1}{2} \Rightarrow 	heta = \frac{\pi }{6}$
$\cos \phi = \frac{1}{3} \Rightarrow \frac{\pi }{3} < \phi < \frac{\pi }{2}

Vedclass · Accepted Answer

$\left( {\frac{\pi }{2},\frac{{2\pi }}{3}} \right)$

Vedclass · Answer

(b) $\sin 	heta = \frac{1}{2} \Rightarrow 	heta = \frac{\pi }{6}$
$\cos \phi = \frac{1}{3} \Rightarrow \frac{\pi }{3} < \phi < \frac{\pi }{2}$. .

Thus, $\frac{\pi }{2} < (	heta + \phi ) < \frac{{2\pi }}{3}$.

If $\theta $ and $\phi $ are acute satisfying $\sin \theta = \frac{1}{2},$ $\cos \phi = \frac{1}{3},$ then $\theta + \phi \in $

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