If $\tan \frac{\theta }{2} = t,$then $\frac{{1 - {t^2}}}{{1 + {t^2}}}$is equal to
If $\tan \frac{\theta }{2} = t,$then $\frac{{1 - {t^2}}}{{1 + {t^2}}}$is equal to
- A
$\cos \theta $
- B
$\sin \theta$
- C
$\sec \theta $
- D
$\cos 2\theta $
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