If $\sin A + \cos A = \sqrt 2 ,$ then ${\cos ^2}A = $
If $\sin A + \cos A = \sqrt 2 ,$ then ${\cos ^2}A = $
- A
$\frac{1}{4}$
- B
$\frac{1}{2}$
- C
$\frac{1}{{\sqrt 2 }}$
- D
$\frac{3}{2}$
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