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Trigonometrical Equations
normal
જો $|cos\ x + sin\ x| + |cos\ x\ -\ sin\ x| = 2\ sin\ x$ ; $x \in [0,2 \pi ]$ થાય તો $x$ ની મહતમ પૂર્ણાક કિમત મેળવો.
A
$1$
B
$2$
C
$3$
D
$4$
Solution
$\cos x\, + \,\sin \,x\, \geqslant \,0\,\ \,\cos \,x\, – \,\sin \,x\, \leqslant \,0$ $ \Rightarrow \,\left[ {\frac{\pi }{4},\frac{{3\pi }}{4}} \right]$
Standard 11
Mathematics