Trigonometrical Equations
normal

જો $|cos\ x + sin\ x| + |cos\ x\ -\ sin\ x| = 2\ sin\ x$ ; $x \in  [0,2 \pi ]$ થાય તો $x$ ની મહતમ પૂર્ણાક કિમત મેળવો.

A

$1$

B

$2$

C

$3$

D

$4$

Solution

$\cos x\, + \,\sin \,x\, \geqslant \,0\,\  \,\cos \,x\, – \,\sin \,x\, \leqslant \,0$ $ \Rightarrow \,\left[ {\frac{\pi }{4},\frac{{3\pi }}{4}} \right]$

Standard 11
Mathematics

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