If a circle of radius $R$ passes through the origin $O$ and intersects the coordinate axes at $A$ and $B,$ then the locus of the foot of perpendicular from $O$ on $AB$ is
If a circle of radius $R$ passes through the origin $O$ and intersects the coordinate axes at $A$ and $B,$ then the locus of the foot of perpendicular from $O$ on $AB$ is
- [JEE MAIN 2019]
- A
${({x^2} + {y^2})^2} = 4{R^2}{x^2}{y^2}$
- B
${({x^2} + {y^2})^3} = 4{R^2}{x^2}{y^2}$
- C
${({x^2} + {y^2})^2} = 4R{x^2}{y^2}$
- D
$({x^2} + {y^2})(x + y) = {R^2}xy$
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