If a function $g(x)$ is defined in $[-1, 1]$ and two vertices of an equilateral triangle are $(0, 0)$ and $(x, g(x))$ and its area is $\frac{\sqrt 3}{4}$ , then $g(x)$ equals :-

  • A

    $\sqrt {1+x^2}$

  • B

    $-\sqrt {1+x^2}$

  • C

    $\sqrt {1-x^2}$ or $-\sqrt {1-x^2}$

  • D

    None of these

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