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8. Sequences and Series
normal
If all interior angle of quadrilateral are in $A.P.$ If common difference is $10^o$, then find smallest angle ? .............. $^o$
A
$60$
B
$70$
C
$120$
D
$75$
Solution
Let Angles are $\rightarrow a-3 d, a-d, a+d, a+3 d$
common difference $\Rightarrow 2 \mathrm{d}=10^{\circ} \Rightarrow \mathrm{d}=5^{\circ}$
$ \operatorname{sum} \Rightarrow 4 a=360 $
$ a =90^{\circ} $
so smallest Angle $\Rightarrow a-3 d=90-3 \times 5^{\circ}=75^{\circ}$
Standard 11
Mathematics