If coefficients of $2^{nd}$, $3^{rd}$ and $4^{th}$ terms in the binomial expansion of ${(1 + x)^n}$ are in $A.P.$, then ${n^2} - 9n$ is equal to

  • A

    $-7$

  • B

    $7$

  • C

    $14$

  • D

    $-14$

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