The value of $x$ satisfying ${\log _a}x + {\log _{\sqrt a }}x + {\log _{3\sqrt a }}x + .........{\log _{a\sqrt a }}x = \frac{{a + 1}}{2}$ will be
The value of $x$ satisfying ${\log _a}x + {\log _{\sqrt a }}x + {\log _{3\sqrt a }}x + .........{\log _{a\sqrt a }}x = \frac{{a + 1}}{2}$ will be
- A
$x = a$
- B
$x = {a^a}$
- C
$x = {a^{ - 1/a}}$
- D
$x = {a^{1/a}}$
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- [JEE MAIN 2020]
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