If sum of n terms of an A.P. is left(p n+q n^{2}right), where p and q are constants, common differen

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8. Sequences and Series

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If the sum of $n$ terms of an $A.P.$ is $\left(p n+q n^{2}\right),$ where $p$ and $q$ are constants, find the common difference.

A

$2 q$

B

$2 q$

C

$2 q$

D

$2 q$

Solution

It is known that: $S_{n}=\frac{n}{2}[2 a+(n-1) d]$

According to the given condition,

$\frac{n}{2}[2 a+(n-1) d]=p n+q n^{2}$

$\Rightarrow \frac{n}{2}[2 a+n d-d]=p n+q n^{2}$

$\Rightarrow n a+n^{2} \frac{d}{2}-n \cdot \frac{d}{2}=p n+q n^{2}$

Comparing the coefficients of $n^{2}$ on both sides, we obtain

$\frac{d}{2}=q$

$\therefore d=2 q$

Thus, the common difference of the $A.P.$ is $2 q$

Standard 11

Mathematics

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