Trigonometrical Equations
hard

If the equation $\cos ^{4} \theta+\sin ^{4} \theta+\lambda=0$ has real solutions for $\theta,$ then $\lambda$ lies in the interval

A

$\left[-\frac{3}{2},-\frac{5}{4}\right]$

B

$\left(-\frac{1}{2},-\frac{1}{4}\right]$

C

$\left(-\frac{5}{4},-1\right)$

D

$\left[-1,-\frac{1}{2}\right]$

(JEE MAIN-2020)

Solution

$\lambda=-\left(\sin ^{4} \theta+\cos ^{4} \theta\right)$

$\lambda=-\left(\sin ^{2} \theta+\cos ^{2} \theta\right)^{2}-2 \sin ^{2} \theta \cos ^{2} \theta$

$\lambda=\frac{\sin ^{2} 2 \theta}{2}-1$

$\lambda \in\left[-1,-\frac{1}{2}\right]$

$\frac{\sin ^{2} 2 \theta}{2} \in\left[0, \frac{1}{2}\right]$

Standard 11
Mathematics

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