If the excess pressure inside a soap bubble is balanced by oil column of height $2\; mm$, then the surface tension of soap solution will be ($r = 1 \,cm$ and density $d = 0.8\, gm/cc$)

A small soap bubble of radius $4\,cm$  is trapped inside another bubble of radius $6\,cm$ without any contact. Let $P_2$  be the pressure inside the inner bubble and $P_0$  the pressure outside the outer bubble. Radius of another bubble with pressure difference $P_2 - P_0$  between its inside and outside would be....... $cm$

A liquid column of height $0.04 \mathrm{~cm}$ balances excess pressure of soap bubble of certain radius. If density of liquid is $8 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}$ and surface tension of soap solution is $0.28 \mathrm{Nm}^{-1}$, then diameter of the soap bubble is . . . . . . .. . $\mathrm{cm}$.

$\text { (if } g=10 \mathrm{~ms}^{-2} \text { ) }$

If pressure at half the depth of a lake is equal to $2/3$ pressure at the bottom of the lake then what is the depth of the lake...... $m$

A soap bubble, blown by a mechanical pump at the mouth of a tube, increases in volume, with time, at a constant rate. The graph that correctly depicts the time dependence of pressure inside the bubble is given by

A drop of water of volume $0.05\, cm^3$ is pressed between two glass plates, as a consequence of which it spreads and occupies an area of $40\, cm^2$. If the surface tension of water is $70\, dyne/cm$, then the normal force required to separate out the two glass plates will be in Newton