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3-1.Vectors
hard
If the projection of $2 \hat{i}+4 \hat{j}-2 \hat{k}$ on $\hat{i}+2 \hat{j}+\alpha \hat{k}$ is zero. Then, the value of $\alpha$ will be.
A
$2$
B
$3$
C
$5$
D
$4$
(JEE MAIN-2022)
Solution
$\overrightarrow{ a } \cdot \overrightarrow{ b }=0$
$\therefore \overrightarrow{ a } \cdot \overrightarrow{ b }=0$
$\therefore 2 \times 1+4 \times 2-2 \times \alpha=0$
$\therefore \alpha=5$
Standard 11
Physics