3-1.Vectors
hard

If the projection of $2 \hat{i}+4 \hat{j}-2 \hat{k}$ on $\hat{i}+2 \hat{j}+\alpha \hat{k}$ is zero. Then, the value of $\alpha$ will be.

A

$2$

B

$3$

C

$5$

D

$4$

(JEE MAIN-2022)

Solution

$\overrightarrow{ a } \cdot \overrightarrow{ b }=0$

$\therefore \overrightarrow{ a } \cdot \overrightarrow{ b }=0$

$\therefore 2 \times 1+4 \times 2-2 \times \alpha=0$

$\therefore \alpha=5$

Standard 11
Physics

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