If the straight line $y = mx + c$ touches the circle ${x^2} + {y^2} - 4y = 0$, then the value of $c$ will be
If the straight line $y = mx + c$ touches the circle ${x^2} + {y^2} - 4y = 0$, then the value of $c$ will be
- A
$1 + \sqrt {1 + {m^2}} $
- B
$1 - \sqrt {{m^2} + 1} $
- C
$2(1 + \sqrt {1 + {m^2}} )$
- D
$2 + \sqrt {1 + {m^2}} $
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- [JEE MAIN 2021]
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